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6a^2-9a-100=0
a = 6; b = -9; c = -100;
Δ = b2-4ac
Δ = -92-4·6·(-100)
Δ = 2481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{2481}}{2*6}=\frac{9-\sqrt{2481}}{12} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{2481}}{2*6}=\frac{9+\sqrt{2481}}{12} $
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